JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Critical Thinking

  • question_answer
    If the dimensions of length are expressed as \[{{G}^{x}}{{c}^{y}}{{h}^{z}}\]; where \[G,\,c\] and \[h\]  are the universal gravitational constant, speed of light and Planck's constant respectively, then    [IIT 1992]

    A)             \[x=\frac{1}{2},\,\,y=\frac{1}{2}\]

    B)                       \[x=\frac{1}{2},\,\,z=\frac{1}{2}\]

    C)             \[y=\frac{1}{2},\,\,z=\frac{3}{2}\]

    D)                      \[y=-\frac{3}{2},\,\,z=\frac{1}{2}\]

    Correct Answer: B

    Solution :

           Length µ Gxcyhz             L= \[{{[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]}^{x}}\,\]\[{{[L{{T}^{-1}}]}^{y}}{{[M{{L}^{2}}{{T}^{-1}}]}^{z}}\] By comparing the power of M, L and T in both sides we get \[-x+z=0\], \[3x+y+2z=1\]and \[-2x-y-z=0\] By solving above three equations we get                         \[x=\frac{1}{2},\,y=-\frac{3}{2},z=\frac{1}{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner