A) \[x=\frac{1}{2},\,\,y=\frac{1}{2}\]
B) \[x=\frac{1}{2},\,\,z=\frac{1}{2}\]
C) \[y=\frac{1}{2},\,\,z=\frac{3}{2}\]
D) \[y=-\frac{3}{2},\,\,z=\frac{1}{2}\]
Correct Answer: B
Solution :
Length µ Gxcyhz L= \[{{[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]}^{x}}\,\]\[{{[L{{T}^{-1}}]}^{y}}{{[M{{L}^{2}}{{T}^{-1}}]}^{z}}\] By comparing the power of M, L and T in both sides we get \[-x+z=0\], \[3x+y+2z=1\]and \[-2x-y-z=0\] By solving above three equations we get \[x=\frac{1}{2},\,y=-\frac{3}{2},z=\frac{1}{2}\]You need to login to perform this action.
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