A) (1, 1)
B) (1, 0)
C) (1, ?1)
D) (0, 0)
Correct Answer: A
Solution :
Given, parabola \[y={{x}^{2}}\] .....(i) Straight line \[y=2x-4\] .....(ii) From (i) and (ii), \[{{x}^{2}}-2x+4=0\] Let \[f(x)={{x}^{2}}-2x+4\], \ \[f'(x)=2x-2\]. For least distance, \[f'(x)=0\] \[\Rightarrow \,2x-2=0\] Þ \[x=1\] From \[y={{x}^{2}}\], \[y=1\] So the point least distant from the line is (1, 1).You need to login to perform this action.
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