A) \[2037.6\times {{10}^{-3}}amp\]
B) \[203.76\times {{10}^{-3}}amp\]
C) \[20.376\times {{10}^{-3}}amp\]
D) \[2.0376\times {{10}^{3}}amp\] \[[\exp (7.62)=2038.6,\,K=1.4\times {{10}^{-23}}J/K]\]
Correct Answer: C
Solution :
The forward current \[i={{i}_{s}}\,({{e}^{eV/kT}}-1)={{10}^{-5}}\,\left[ {{e}^{\frac{1.6\times {{10}^{-19}}\times \,0.2}{1.4\times {{10}^{-23}}\times \,300}}}-1 \right]\] \[={{10}^{-5}}\,[2038.6-1]=20.376\times {{10}^{-3}}A\]You need to login to perform this action.
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