2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Nuclear Physics And Radioactivity

JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Critical Thinking

  • question_answer
    An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is                                       [IIT 1995]

    A)            79.0                                          

    B)            51.8

    C)            49.2                                          

    D)            38.2

    Correct Answer: A

    Solution :

               After the removal of first electron remaining atom will be hydrogen like atom.                    So energy required to remove second electron from the atom \[E=13.6\times \frac{{{2}^{2}}}{1}=54.4\,eV\]            \ Total energy required = 24.6 + 54.4 = 79 eV.


You need to login to perform this action.
You will be redirected in 3 sec spinner