A) 21.2 cc
B) 15.2 cc
C) 1.52 cc
D) 2.12 cc
Correct Answer: B
Solution :
Due to volume expansion of both liquid and vessel, the change in volume of liquid relative to container is given by DV = \[{{V}_{0}}[{{\gamma }_{L}}-{{\gamma }_{g}}]\Delta \theta \] Given V0 = 1000 cc, ag = 0.1×10?4/°C \\[{{\gamma }_{g}}=3{{\alpha }_{g}}=3\times 0.1\times {{10}^{-4}}/{}^\circ C=0.3\times {{10}^{-4}}/{}^\circ C\] \ DV = 1000 [1.82 × 10?4 ? 0.3 × 10?4] × 100 = 15.2 cc
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