JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Critical Thinking

  • question_answer
    A conducting ring of radius 1 meter is placed in an uniform magnetic field B of 0.01Telsa oscillating with frequency 100Hz with its plane at right angles to B. What will be the induced electric field                                [AIIMS 2005]

    A)            \[\pi \,volt/m\]                   

    B)            \[2\,volt/m\]

    C)            \[10\,volt/m\]                     

    D)            \[62\,volt/m\]

    Correct Answer: B

    Solution :

                       In a constant magnetic field conducting ring oscillates with a frequency of 100 Hz. i.e. \[T=\frac{1}{100}s,\]in time \[\frac{T}{2}\] flux links with coil changes from  \[BA\] to zero. Þ Induced emf = \[\frac{\text{change in flux}}{\text{time}}\]                    \[=\frac{BA}{T/2}=\frac{2BA}{T}\]\[=\frac{2B\times \pi {{r}^{2}}}{T}\]\[=\frac{2\times 0.01\times \pi \times {{1}^{2}}}{1/100}=4\pi V\]                               Induced electric field along the circle, using Maxwell equation    \[\oint{E.dl=-\frac{d\varphi }{dt}}\]\[=A\frac{dB}{dt}=e\]                    Þ \[E=\frac{1}{2\pi r}\times \left( \pi {{r}^{2}}\times \frac{dB}{dt} \right)=\frac{e}{2\pi r}=\frac{4\pi }{2\pi r}=2\,V/m\]


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