A) 1 A
B) 4 A
C) 2 A
D) 3 A
Correct Answer: C
Solution :
\[-\,{{i}_{1}}+0\times {{i}_{xy}}+3{{i}_{2}}=0\]i.e. \[{{i}_{1}}=3{{i}_{2}}\] ......(i) Also \[-2({{I}_{1}}-{{I}_{xy}})+4({{I}_{2}}+{{I}_{xy}})=0\] i.e. \[2{{I}_{1}}-4{{I}_{2}}=6{{I}_{xy}}\] ....(ii) Also \[{{V}_{AB}}-1\times {{i}_{1}}-2({{i}_{1}}-{{i}_{xy}})=0\]Þ \[50={{i}_{1}}+2({{i}_{1}}-{{i}_{xy}})\] \[=3{{I}_{1}}-2{{I}_{xy}}\] .... (iii) Solving (i), (ii) and (iii), \[{{i}_{xy}}=2A\]
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