JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Critical Thinking

  • question_answer
    A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field \[\vec{B}\] directed into the paper. AO = l and OC = 3l. Then

    A)            \[{{V}_{A}}-{{V}_{O}}=\frac{B\omega {{l}^{2}}}{2}\]

    B)            \[{{V}_{O}}-{{V}_{C}}=\frac{7}{2}B\omega {{l}^{2}}\]

    C)            \[{{V}_{A}}-{{V}_{C}}=4B\omega {{l}^{2}}\]

    D)            \[{{V}_{C}}-{{V}_{O}}=\frac{9}{2}B\omega {{l}^{2}}\]

    Correct Answer: C

    Solution :

                       By using \[e=\frac{1}{2}B{{l}^{2}}\omega \] For part AO ; \[{{e}_{OA}}={{e}_{O}}-{{e}_{A}}=\frac{1}{2}B{{l}^{2}}\omega \] For part OC; \[{{e}_{OC}}={{e}_{O}}-{{e}_{C}}=\frac{1}{2}B{{(3l)}^{2}}\omega \] \[\therefore {{e}_{A}}-{{e}_{C}}=4\ B{{l}^{2}}\omega \]


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