JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    Angular width of central maxima in the Fraunhoffer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength \[6000\,{AA}\]. When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will be

    A) \[6000\,\,{AA}\]               

    B) \[4200\,\,{AA}\]

    C) \[3000\,\,{AA}\]               

    D) \[1800\,\,{AA}\]

    Correct Answer: B

    Solution :

    Angular width \[\beta \]\[=\frac{2\lambda }{d}\] \[\Rightarrow \frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\Rightarrow \frac{\beta }{\frac{70}{100}\beta }=\frac{6000}{{{\lambda }_{2}}}\Rightarrow {{\lambda }_{2}}=4200\,{AA}\]


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