JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Critical Thinking

  • question_answer
    A radioactive isotope X with a half-life of \[1.37\times {{10}^{9}}\] years decays to Y which is stable. A sample of rock from the moon was found to contain both the elements X and Y which were in the ratio of 1 : 7. The age of the rock is

    A)            \[1.96\times {{10}^{8}}\]years                                         

    B)            \[3.85\times {{10}^{9}}\]years

    C)            \[4.11\times {{10}^{9}}\]years                                         

    D)            \[9.59\times {{10}^{9}}\]years

    Correct Answer: C

    Solution :

               If in the rock there is no Y element, then the time taken by element X to reduce to \[\frac{1}{8}th\] the initial value will be equal to \[\frac{1}{8}={{\left( \frac{1}{2} \right)}^{n}}\]or n =3 Therefore, from the beginning three half life time is spent. Hence the age of the rock is \[=\lambda N=\lambda {{N}_{0}}{{\left( \frac{1}{2} \right)}^{\frac{9}{3}}}=\frac{\lambda {{N}_{0}}}{8}\].


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