JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    The temperature of hot junction of a thermo-couple changes from \[{{80}^{o}}C\] to \[{{100}^{o}}C.\] The percentage change in thermoelectric power is

    A)            8% 

    B)            10%

    C)            20%                                          

    D)            25%

    Correct Answer: D

    Solution :

                       Thermoelectric power \[P\propto \theta \] Þ \[\frac{{{P}_{100}}-{{P}_{80}}}{{{P}_{80}}}\times 100=\frac{100-80}{80}\times 100\]= 25%


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