A) 2 : 1
B) 1 : 16
C) 4 : 1
D) 16 : 1
Correct Answer: D
Solution :
\[H={{i}^{2}}RT={{i}^{2}}\left( \frac{\rho l}{A} \right)\,t=\frac{{{i}^{2}}\rho Vt}{{{A}^{2}}}\] (V = volume, = Al) Þ \[H\propto \frac{1}{{{r}^{4}}}\] Þ \[\frac{{{H}_{1}}}{{{H}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}={{\left( \frac{2}{1} \right)}^{4}}=\frac{16}{1}\].
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