JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Critical Thinking

  • question_answer
    The edge of a cube is of length -a- then the shortest distance between the diagonal of a cube and an edge skew to it is

    A) \[a\sqrt{2}\]

    B) a

    C) \[\sqrt{2}/a\]

    D) \[a/\sqrt{2}\]

    Correct Answer: D

    Solution :

                                              
    • Requaried distance = KL                                                              
    • \[=\sqrt{{{\left( a-\frac{a}{2} \right)}^{2}}+{{0}^{2}}+{{\left( 0-\frac{a}{2} \right)}^{2}}}\]\[=\frac{a}{\sqrt{2}}\].


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