JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Critical Thinking

  • question_answer
    In X-ray tube when the accelerating voltage V is halved, the difference between the wavelength of Ka line and minimum wavelength of continuous X-ray spectrum

    A)            Remains constant              

    B)            Becomes more than two times

    C)            Becomes half                       

    D)            Becomes less than two times

    Correct Answer: D

    Solution :

                       \[\Delta \lambda ={{\lambda }_{{{K}_{\alpha }}}}-{{\lambda }_{\min }}\] When V is halved \[{{\lambda }_{\min }}\] becomes two times but \[{{\lambda }_{{{K}_{\alpha }}}}\]remains the same.                    \      \[\Delta \lambda '={{\lambda }_{{{K}_{\alpha }}}}-2{{\lambda }_{\min }}\]\[=2(\Delta \lambda )-{{\lambda }_{{{K}_{a}}}}\]                    \      \[\Delta \lambda \,'<2\,(\Delta \lambda )\]


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