A) 4.12 gm
B) 4.12 kg
C) 3.68 kg
D) 2.625 gm
Correct Answer: D
Solution :
\[\frac{Q}{t}=\frac{{{V}^{2}}}{4.2\,\,R}=\frac{m}{t}.L\] \ \[\frac{m}{t}=\frac{{{V}^{2}}}{4.2\,\,RL}=\frac{{{(210)}^{2}}}{4.2\times 50\times 80}\approx 2.625\,\,gm\]
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