• # question_answer 33) If $(x+1)$ is a factor of${{x}^{4}}-(p-3){{x}^{3}}-(3p-5){{x}^{2}}$ $+(2p-7)x+6$, then $p=$ [IIT 1975] A) 4 B) 2 C) 1 D) None of these

If $(x+1)$ is a factor of ${{x}^{4}}-(p-3){{x}^{3}}-(3p-5){{x}^{2}}+(2p-7)x+6$ , then by putting$x=-1$, we get $1+(p-3)-(3p-5)-(2p-7)+6=0$ Þ $-4p=-16\,\,\,\Rightarrow p=4$.