JEE Main & Advanced Mathematics Functions Question Bank Critical Thinking

  • question_answer
    The function\[f(x)=[x]\cos \left[ \frac{2x-1}{2} \right]\pi ,\,\]where\[[.]\] denotes the greatest integer function, is discontinuous at               [IIT 1995]

    A) All x

    B) No x

    C) All integer points

    D) x which is not an integer

    Correct Answer: C

    Solution :

    • \[f(x)=[x]\cos \,\left[ \frac{2x-1}{2} \right]\,\pi \]           
    • Since \[g(x)=[x]\] is always discontinuous at all integral values of points. Hence \[f(x)\] is discontinuous for all integral points.


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