A) 1 : 2 : 8
B) 1 : 2 : 4
C) 1 : 1 : 2
D) None of these
Correct Answer: A
Solution :
The deflection suffered by charged particle in an electric field is \[y=\frac{q\,ELD}{m\,{{u}^{2}}}=\frac{q\,ELD}{{{p}^{2}}/m}\] (p =mu) Þ \[y\propto \frac{qm}{{{p}^{2}}}\] Þ yp : yd : ya \[=\frac{{{q}_{p}}{{m}_{p}}}{p_{p}^{2}}:\frac{{{q}_{d}}{{m}_{d}}}{p_{d}^{2}}:\frac{{{q}_{\alpha }}{{m}_{\alpha }}}{p_{\alpha }^{2}}\] Since pa = pd = pp (given) mp : md : ma = 1 : 2 : 4 and qp : qd : qa = 1 : 1 : 2 Þ yp : yd : ya = 1 ´1 : 1 ´ 2 : 2 ´ 4 = 1 : 2 : 8
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