question_answer

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is

A)           0      

B)           1.41 volt

C)           0.71 volt                                

D)           None of the above

Correct Answer: B

Solution :

                   There is no induced emf in the part AB and CD because they are moving along their length while emf induced between B and C i.e. between A and D can be calculated as follows                              Induced emf between B and C = Induced emf between A and B = \[Bv(\sqrt{2}\,l)=1\times 1\times 1\times \sqrt{2}=1.41\,volt.\]