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JEE Main & Advanced Physics Wave Mechanics Question Bank Critical Thinking

  • question_answer
    The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N, it is in resonance with the first overtone of the closed tube. The initial tension in the wire is                [EAMCET (Engg.) 2000]

    A)            1 N

    B)            4 N

    C)            8 N

    D)            16 N

    Correct Answer: A

    Solution :

                       According to problem                    \[\frac{1}{2L}\sqrt{\frac{T}{m}}=\frac{v}{4L}\] ?..(i)                    and \[\frac{1}{2L}\sqrt{\frac{T+8}{m}}=\frac{3v}{4L}\]                 ..?(ii)                    Dividing equation (i) and (ii),  \[\sqrt{\frac{T}{T+8}}=\frac{1}{3}\Rightarrow T=1N\]


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