A) 30 K
B) 18 K
C) 50 K
D) 42 K
Correct Answer: D
Solution :
In both cylinders A and B the gases are diatomic (g = 1.4). Piston A is free to move i.e. it is isobaric process. Piston B is fixed i.e. it is isochoric process. If same amount of heat DQ is given to both then \[{{(\Delta Q)}_{\text{isobaric}}}={{(\Delta Q)}_{\text{isochoric}}}\]Þ \[\mu \,{{C}_{p}}{{(\Delta T)}_{A}}=\mu \,{{C}_{v}}{{(\Delta T)}_{B}}\] Þ\[{{(\Delta T)}_{B}}=\frac{{{C}_{p}}}{{{C}_{v}}}{{(\Delta T)}_{A}}=\gamma {{(\Delta T)}_{A}}=1.4\times 30=42\,K.\]
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