A) \[2\pi \sqrt{\frac{M\eta }{L}}\]
B) \[2\pi \sqrt{\frac{L}{M\eta }}\]
C) \[2\pi \sqrt{\frac{ML}{\eta }}\]
D) \[2\pi \sqrt{\frac{M}{\eta L}}\]
Correct Answer: D
Solution :
By substituting the dimensions of mass [M], length [L] and coefficient of rigidity \[\left[ M{{L}^{-1}}{{T}^{-2}} \right]\] we get \[T=2\pi \sqrt{\frac{M}{\eta L}}\]is the right formula for time period of oscillationsYou need to login to perform this action.
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