A) \[5\times {{10}^{-7}}T\]
B) \[\sqrt{5}\times {{10}^{-7}}T\]
C) \[{{10}^{-7}}T\]
D) None of these
Correct Answer: B
Solution :
With respect to 1st magnet, P lies in end side-on position \[\therefore {{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }\left( \frac{2M}{{{d}^{3}}} \right)\] (RHS)You need to login to perform this action.
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