A) 0.28 MeV
B) 0.34 MeV
C) 0.39 MeV
D) 0.46 MeV
Correct Answer: B
Solution :
Given m0c2 = 0.51 MeV and v = 0.8 c K.E. of the electron = mc2? m0c2 But \[m=\frac{{{m}_{0}}}{\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}}=\frac{{{m}_{0}}}{\sqrt{1-{{\left( \frac{0.8\,c}{c} \right)}^{2}}}}=\frac{{{m}_{0}}}{\sqrt{0.36}}=\frac{{{m}_{0}}}{0.6}\] Now, \[m{{c}^{2}}=\frac{0.51}{0.6}\] MeV = 0.85 MeV \ K.E. = (0.85 ? 0.51)MeV = 0.34 MeV.
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