A) 0.026 MeV
B) 0.051 MeV
C) 0.079 MeV
D) 0.105 MeV
Correct Answer: C
Solution :
\[\Delta =m{{c}^{2}}-{{m}_{0}}{{c}^{2}}=\frac{{{m}_{0}}{{c}^{2}}}{\sqrt{1-({{v}^{2}}/{{c}^{2}})}}-{{m}_{0}}{{c}^{2}}\] \[={{m}_{0}}{{c}^{2}}\left( \frac{1}{\sqrt{1-({{v}^{2}}/{{c}^{2}})}}-1 \right)=0.511\,\left( \frac{1}{\sqrt{0.75}}-1 \right)\] = 0.079MeV
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