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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Critical Thinking

  • question_answer
    P-V diagram of a diatomic gas is a straight line passing through origin. The molar heat capacity of the gas in the process will be

    A)            4 R 

    B)            2.5 R

    C)            3 R 

    D)            \[\frac{4R}{3}\]

    Correct Answer: C

    Solution :

                       P-V diagram of the gas is a straight line passing through origin. Hence \[P\propto V\] or \[P{{V}^{-1}}=\] constant                    Molar heat capacity in the process \[P{{V}^{x}}=\text{constant is }\]                        \[C=\frac{R}{\gamma -1}+\frac{R}{1-x}\]; Here \[\gamma =1.4\]   (For diatomic gas)            Þ \[C=\frac{R}{1.4-1}+\frac{R}{1+1}\] Þ \[C=3R\]


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