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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Critical Thinking

  • question_answer
    The binding energy per nucleon of \[{{O}^{16}}\]is 7.97 MeV and that of \[{{O}^{17}}\]is 7.75 MeV. The energy (in MeV)            required to remove a neutron from \[{{O}^{17}}\]is             [IIT 1995]

    A)            3.52                                          

    B)            3.64

    C)            4.23                                          

    D)            7.86

    Correct Answer: C

    Solution :

               The equation is \[{{O}^{17}}{{\to }_{0}}{{n}^{1}}+{{O}^{16}}\]                    \[\therefore \]Energy required = B.E. of O17 ? B.E. of O16            = 17 ´ 7.75 ? 16 ´ 7.97 = 4.23 MeV                                  


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