A) Z = 6
B) Z = 4
C) Z = 11
D) Z = 44
Correct Answer: A
Solution :
\[\sqrt{{{f}_{1}}}=\sqrt{\frac{v}{{{\lambda }_{1}}}}=a\left( 11-1 \right)\] and \[\sqrt{{{f}_{2}}}=\sqrt{\frac{v}{{{\lambda }_{2}}}}=a\left( Z-1 \right)\] By dividing, \[\sqrt{\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}}=\frac{10}{Z-1}\]Þ\[\sqrt{\frac{4}{1}}=\frac{10}{Z-1}\]Þ Z = 6
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