A) 3.2
B) 1.6
C) 0.2
D) 0.1
Correct Answer: C
Solution :
\[\frac{Q}{t}=\frac{KA\Delta \theta }{l}\]Þ \[\frac{mL}{t}\] \[=\frac{K(\pi {{r}^{2}})\Delta \theta }{l}\] Þ Rate of melting of ice \[\left( \frac{m}{t} \right)\propto \frac{K{{r}^{2}}}{l}\] Since for second rod K becomes \[\frac{1}{4}th\] r becomes double and length becomes half, so rate of melting will be twice i.e. \[{{\left( \frac{m}{t} \right)}_{2}}=2\,{{\left( \frac{m}{t} \right)}_{1}}=2\times 0.1=0.2\,gm/sec.\]
You need to login to perform this action.
You will be redirected in
3 sec
