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JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Critical Thinking

  • question_answer
    The line \[\frac{x-3}{2}=\frac{y-4}{3}=\frac{z-5}{4}\] lies in the plane \[4x+4y-kz-d=0\]. The values of k and d are

    A) 4, 8

    B) -5, -3

    C) 5, 3

    D) - 4, - 8

    Correct Answer: C

    Solution :

    Since the line lies on the given plane, therefore any point on the line will satisfy the plane i.e., the points (3, 4, 5) and (5, 7, 9) will lie on the plane. Hence \[k=5,\,\,d=3.\]


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