A) 6 ergs
B) \[6\times {{10}^{-7}}\,ergs\]
C) 16 ergs
D) \[6\times {{10}^{-3}}\,\,erg\]
Correct Answer: A
Solution :
\[H=\pi it=(2\times {{10}^{-9}})\times 2.5\times (2\times 60)=6\times {{10}^{-7}}\,J=6\,erg\]
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