A) \[{{10}^{-4}}M\,C{{a}^{2+}}\] and \[{{10}^{-4}}M\,{{F}^{-}}\]
B) \[{{10}^{-2}}M\,C{{a}^{2+}}\] and \[{{10}^{-3}}M\,{{F}^{-}}\]
C) \[{{10}^{-5}}M\,C{{a}^{2+}}\] and \[{{10}^{-4}}M\,{{F}^{-}}\]
D) \[{{10}^{-3}}M\,C{{a}^{2+}}\] and \[{{10}^{-4}}M\,{{F}^{-}}\]
Correct Answer: B
Solution :
\[[C{{a}^{2+}}]\,\,{{[{{F}^{-}}]}^{2}}=\left[ \frac{{{10}^{-2}}\times V}{2V} \right]\times {{\left[ \frac{{{10}^{-3}}\times V}{2V} \right]}^{2}}\]\[=1.25\times {{10}^{-9}}\].
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