A) \[{{20}^{o}}C\]
B) \[{{16}^{o}}C\]
C) \[{{12}^{o}}C\]
D) \[{{8}^{o}}C\]
Correct Answer: B
Solution :
\[e=iR\] Þ \[25\times {{10}^{-6}}\times \Delta \theta ={{10}^{-5}}\times 40\] \[\Delta \theta =\frac{40\times {{10}^{-5}}}{25\times {{10}^{-6}}}=\frac{400}{25}=16{}^\circ C\]You need to login to perform this action.
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