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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    Self-ionisation of liquid ammonia occurs as, \[2N{{H}_{3}}\]⇄\[NH_{4}^{+}+NH_{2}^{-};\,K={{10}^{-10}}\]. In this solvent, an acid might be  [JIPMER 2001]

    A)                 \[NH_{4}^{+}\]

    B)                 \[N{{H}_{3}}\]

    C)                 Any species that will form \[NH_{4}^{+}\]

    D)                 All of these                

    Correct Answer: A

    Solution :

                    A substance which can donate a proton is known as acid so \[NH_{4}^{+}\] will be a acid.


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