A) 0.51MeV
B) 1.2 MeV
C) 59 KeV
D) 13.6 eV
Correct Answer: C
Solution :
\[{{E}_{K}}-{{E}_{L}}=\frac{hc}{\lambda }\]\[=\frac{(6.6\times {{10}^{-34}})\,\,(3\times {{10}^{8}})}{(0.021\times {{10}^{-9}})\,\,(1.6\times {{10}^{-19}})}eV\]=59keVYou need to login to perform this action.
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