A) 200 sec
B) 150 sec
C) 836 sec
D) 418 sec
Correct Answer: B
Solution :
\[W=JH\] Þ \[P\times t=J\times m\,s\,\Delta \theta \] Þ \[t=\frac{J\times m\times s\Delta \theta }{P}\] (For water 1 litre = 1kg) Þ \[t=\frac{4.2\times 1\times 1000\times (40-10)}{836}=150\,sec\] Short Trick: use formula \[t=\frac{4200\times m\times \Delta \theta }{P}\]
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