• question_answer In equations $3x-y\ge 3$ and $4x-y>4$             [MP PET 2001] A)                 Have solution for positive x and y             B)                 Have no solution for positive x and y C)                 Have solution for all x D)                 Have solution for all y

Following figure will be obtained on drawing the graphs of given in equations.                    From $3x-y\ge 3,\frac{x}{1}+\frac{y}{-3}=1$                    From $4x-y>4,\,\frac{x}{1}+\frac{y}{-4}=1$                                 Clearly the common region of both is true for positive value of (x, y). It is also true for positive value of x and negative value of y.