JEE Main & Advanced Mathematics Linear Programming Question Bank Critical Thinking

  • question_answer In equations \[3x-y\ge 3\] and \[4x-y>4\]             [MP PET 2001]

    A)                 Have solution for positive x and y            

    B)                 Have no solution for positive x and y

    C)                 Have solution for all x

    D)                 Have solution for all y

    Correct Answer: A

    Solution :

               Following figure will be obtained on drawing the graphs of given in equations.                    From \[3x-y\ge 3,\frac{x}{1}+\frac{y}{-3}=1\]                    From \[4x-y>4,\,\frac{x}{1}+\frac{y}{-4}=1\]                                 Clearly the common region of both is true for positive value of (x, y). It is also true for positive value of x and negative value of y.

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