A) \[\frac{IL}{4\pi }\]
B) \[\frac{I{{L}^{2}}}{4\pi }\]
C) \[\frac{{{I}^{2}}{{L}^{2}}}{4\pi }\]
D) \[\frac{{{I}^{2}}L}{4\pi }\]
Correct Answer: B
Solution :
If the radius of circle is r, then \[2\pi r=L\Rightarrow r=\frac{L}{2\pi }\] Area \[=\pi {{r}^{2}}=\frac{\pi {{L}^{2}}}{4{{\pi }^{2}}}=\frac{{{L}^{2}}}{4\pi }\] Magnetic moment \[=IA=\frac{I{{L}^{2}}}{4\pi }\]
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