A) \[\frac{1}{2}K{{T}_{0}}\]
B) \[K{{T}_{0}}\]
C) \[\frac{1}{2}KT_{0}^{2}\]
D) \[\frac{1}{2}K{{({{T}_{0}}-{{T}_{r}})}^{2}}\]
Correct Answer: A
Solution :
We know that thermoelectric power \[S=\frac{dE}{dT}\] Given \[E=k\,(T-{{T}_{r}})\,\left[ {{T}_{0}}-\frac{1}{2}(T+{{T}_{r}}) \right]\] By differentiating the above equation w.r.t. T and Putting \[T=\frac{1}{2}{{T}_{o}},\] we get \[S=\frac{1}{2}k{{T}_{o}}\]
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