JEE Main & Advanced Mathematics Quadratic Equations Question Bank Critical Thinking

  • question_answer If a root of the given equation \[a(b-c){{x}^{2}}+b(c-a)x+c(a-b)=0\]is 1, then the other will be    [RPET 1986]

    A) \[\frac{a(b-c)}{b(c-a)}\]

    B) \[\frac{b(c-a)}{a(b-c)}\]

    C) \[\frac{c(a-b)}{a(b-c)}\]

    D) None of these

    Correct Answer: C

    Solution :

    Let \[\alpha =1\] and the other root is\[\beta \], then product of roots 1. \[\beta =\frac{c(a-b)}{a(b-c)}\Rightarrow \beta =\frac{c(a-b)}{a(b-c)}\]

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