A) \[{{H}_{2}}\],\[{{H}_{3}}B{{O}_{3}}\]
B) \[HCl\],\[KB{{O}_{3}}\]
C) \[{{H}_{2}}O,\,\,KB{{O}_{3}}\]
D) \[{{H}_{2}}O\],\[KB{{O}_{2}}\]
Correct Answer: D
Solution :
\[{{B}_{2}}{{H}_{6}}+2KOH+2{{H}_{2}}O\to 2KB{{O}_{2}}+6{{H}_{2}}\].
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