A) For bigger ball
B) For smaller ball
C) Equal for both the balls
D) None is correct from the above three
Correct Answer: C
Solution :
Energy = \[\frac{1}{2}m{{v}^{2}}\] = mc Dq; Þ \[\Delta \theta \propto {{v}^{2}}\] Temperature does not depend upon the mass of the balls.
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