A) 1 Å
B) 2 Å
C) 10 Å
D) 20 Å
Correct Answer: D
Solution :
Bragg's law, \[2d\sin \theta =n\lambda \] or \[\lambda =\frac{2d\sin \theta }{n}\] For maximum wavelength, \[{{n}_{\min }}=1,\,\,{{(\sin \theta )}_{\max }}=1\] \[\therefore \,\,{{\lambda }_{\max }}=2d\] or \[{{\lambda }_{\max }}=2\times {{10}^{-7}}cm=20\,{\AA}\]
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