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JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry / रसायन की कुछ मूलभूत अवधारणाएँ Question Bank Critical Thinking

  • question_answer
    A 100 ml solution of 0.1 n HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is        [DCE 1999]

    A)                 70 ml     

    B)                 32 ml

    C)                 35 ml     

    D)                 16 ml

    Correct Answer: D

    Solution :

               Volume m of HCl neutralised by NaOH = (Caustic soda) = \[{{V}_{1}}\]                    \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\]; \[0.1\times {{V}_{1}}=0.2\times 30\]; \[{{V}_{1}}=60ml\]                    V total (HCl) = 100ml                    \[{{V}_{1}}\]               = 60ml                    _________________                                            40ml                    40ml 0.1N HCl is now neutralised by KOH (0.25N) \[\to \]                    (HCl) \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\](KOH)                                 \[0.1\times 40=0.25\times {{V}_{2}}\];                   \[{{V}_{2}}=16ml\].


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