JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Critical Thinking

  • question_answer
    2 kg of ice at ? 20°C is mixed with 5 kg of water at 20°C in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1 kcal/kg per °C and 0.5 kcal/kg/°C while the latent heat of fusion of ice is 80 kcal/kg [IIT-JEE (Screening) 2003]

    A)            7 kg                                          

    B)            6 kg

    C)            4 kg                                          

    D)            2 kg

    Correct Answer: B

    Solution :

                       Initially ice will absorb heat to raise it's temperature to 0oC then it's melting takes place If mi = Initial mass of ice, mi' = Mass of ice that melts and mW = Initial mass of water By Law of mixture Heat gained by ice = Heat lost by water  Þ  \[{{m}_{i}}\times c\times (20)+{{m}_{i}}'\,\times L\] = \[{{m}_{W}}{{c}_{W}}[20]\] Þ  \[2\times 0.5(20)+{{m}_{i}}'\times 80\] = \[5\times 1\times 20\] Þ \[{{m}_{i}}'\]= 1kg  So final mass of water = Initial mass of water + Mass of ice that melts = 5 + 1= 6 kg.


You need to login to perform this action.
You will be redirected in 3 sec spinner