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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Critical Thinking

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    If in Rutherford?s experiment, the number of particles scattered at \[{{90}^{o}}\]angle are 28 per min, then number of scattered particles at an angle \[{{60}^{o}}\] and \[{{120}^{o}}\] will be  [UPSEAT 1999]

    A)            112/min, 12.5/min             

    B)            100/min, 200/min

    C)            50/min, 12.5/min               

    D)            117/min, 25/min

    Correct Answer: A

    Solution :

               \[N\propto \left[ \frac{1}{{{\sin }^{4}}\theta /2} \right]\] Þ \[{{N}_{1}}=7\times \frac{1}{{{(\sin {{30}^{o}})}^{4}}}=112\]                     and \[{{N}_{2}}=7\times \frac{1}{{{(\sin {{60}^{o}})}^{4}}}=12.5\].


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