JEE Main & Advanced Physics Thermodynamical Processes Question Bank Critical Thinking

  • question_answer
    An insulator container contains 4 moles of an ideal diatomic gas at temperature T. Heat Q is supplied to this gas, due to which 2 moles of the gas are dissociated into atoms but temperature of the gas remains constant. Then

    A)            \[Q=2RT\]                             

    B)            \[Q=RT\]

    C)            \[Q=3RT\]                             

    D)            \[Q=4RT\]

    Correct Answer: B

    Solution :

                       \[Q=\Delta U\]\[={{U}_{f}}-{{U}_{i}}\] = [internal energy of 4 moles of a monoatomic gas + internal energy of 2 moles of a diatomic gas] ? [internal energy of 4 moles of a diatomic gas]                    \[=\left( 4\times \frac{3}{2}RT+2\times \frac{5}{2}RT \right)-\left( 4\times \frac{5}{2}RT \right)\] = RT Note :  2 moles of diatomic gas becomes 4 moles of a monoatomic gas when gas dissociated into atoms.  Internal energy of m moles of an ideal gas of degrees of freedom F is given by \[U=\frac{f}{2}\mu RT\] F = 3 for a monoatomic gas and 5 for diatomic gas.


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