A) \[k=1\]
B) \[k=2\]
C) \[k=3\]
D) None of these
Correct Answer: B
Solution :
Given equation can be written as \[{{x}^{2}}-3kx+2{{k}^{2}}-1=0\] So the product of roots is \[2{{k}^{2}}-1\]. But the product of roots is 7. Hence \[2{{k}^{2}}-1=7\Rightarrow 2{{k}^{2}}=8\Rightarrow k=\pm 2\] But k cannot be negative.You need to login to perform this action.
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