A) \[{{E}_{0}}=-\ 27.2\ eV;\ {{r}_{0}}={{a}_{0}}/2\]
B) \[{{E}_{0}}=-\ 27.2\ eV;\ {{r}_{0}}={{a}_{0}}\]
C) \[{{E}_{0}}=-13.6\ eV;\ {{r}_{0}}={{a}_{0}}/2\]
D) \[{{E}_{0}}=-13.6\ eV;\ {{r}_{0}}={{a}_{0}}\]
Correct Answer: A
Solution :
Here radius of electron orbit \[r\propto 1/m\]and energy E µ m, where m is the mass of the electron. Hence energy of hypothetical atom \[{{E}_{0}}=2\times (-13.6\,eV)=-27.2\,eV\] and radius \[{{r}_{0}}=\frac{{{a}_{0}}}{2}\]
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