A) 2p
B) 5p
C) p
D) 4p
Correct Answer: B
Solution :
\[e=M\frac{di}{dt}=0.005\times \frac{d}{dt}({{i}_{0}}\sin \omega t)\]\[=0.005\times {{i}_{0}}\omega \cos \omega \,t\] \[\therefore {{e}_{\max }}=0.005\times 10\times 100\pi =5\pi \]
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